3x^2-12=3(x-2)(x+2)

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Solution for 3x^2-12=3(x-2)(x+2) equation: 


Simplifying
3x2 + -12 = 3(x + -2)(x + 2)

Reorder the terms:
-12 + 3x2 = 3(x + -2)(x + 2)

Reorder the terms:
-12 + 3x2 = 3(-2 + x)(x + 2)

Reorder the terms:
-12 + 3x2 = 3(-2 + x)(2 + x)

Multiply (-2 + x) * (2 + x)
-12 + 3x2 = 3(-2(2 + x) + x(2 + x))
-12 + 3x2 = 3((2 * -2 + x * -2) + x(2 + x))
-12 + 3x2 = 3((-4 + -2x) + x(2 + x))
-12 + 3x2 = 3(-4 + -2x + (2 * x + x * x))
-12 + 3x2 = 3(-4 + -2x + (2x + x2))

Combine like terms: -2x + 2x = 0
-12 + 3x2 = 3(-4 + 0 + x2)
-12 + 3x2 = 3(-4 + x2)
-12 + 3x2 = (-4 * 3 + x2 * 3)
-12 + 3x2 = (-12 + 3x2)

Add '12' to each side of the equation.
-12 + 12 + 3x2 = -12 + 12 + 3x2

Combine like terms: -12 + 12 = 0
0 + 3x2 = -12 + 12 + 3x2
3x2 = -12 + 12 + 3x2

Combine like terms: -12 + 12 = 0
3x2 = 0 + 3x2
3x2 = 3x2

Add '-3x2' to each side of the equation.
3x2 + -3x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
0 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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